A lemmy community for the logic puzzle game minesweeper.
This was a rare moment where I actually had to think to find it. Can you?
Screenshot is from a solver I found online because I didn't think to take a screenshot until I already opened the safe square.
It's interesting to see two answers having directly opposing answers.
But I do believe >!the 4/2/1 corner must be a bomb, the one above must be safe!<
That is correct! The spoiler markdown doesn't work on my end (browser on desktop) but the others didn't even bother, so no matter!
The corner of 1,2,4 on the left must be a bomb.
In the bottom gap, either side of the 1 being a bomb causes the 1,2,4 corner to be a bomb.
If the bomb is right of the 1, then the square above and below the 4 must be bombs because of the 2.
If the bomb is to the left of 1, the 2,2,3,3 forces one of the squares below the second 2 to be a bomb, which means the square below the 4 must be safe, so the square above 4 must be a bomb.
If the bomb is to the left of the one, there could still be another bomb directly next to it, no?
No, the 3 below the two 1s has a shared partner with the 2 to it's left. So because it has a bomb directly above it, it must have one more below it. Therefore the space under the 4 would be empty and the space above it would have to be a bomb for the upper 2.
Got it now, you're very right. I didn't evaluate that 3 correctly at all.
Top blank square. The two 1’s at the bottom prove it. Bottom 1 has two unknowns. Which means one of them is the bomb. Which means the bottom mystery square can’t be the bomb which means the top square is the bomb.