this post was submitted on 02 Dec 2023
146 points (95.6% liked)
Advent Of Code
763 readers
1 users here now
An unofficial home for the advent of code community on programming.dev!
Advent of Code is an annual Advent calendar of small programming puzzles for a variety of skill sets and skill levels that can be solved in any programming language you like.
AoC 2023
Solution Threads
| M | T | W | T | F | S | S |
|---|---|---|---|---|---|---|
| 1 | 2 | 3 | ||||
| 4 | 5 | 6 | 7 | 8 | 9 | 10 |
| 11 | 12 | 13 | 14 | 15 | 16 | 17 |
| 18 | 19 | 20 | 21 | 22 | 23 | 24 |
| 25 |
Rules/Guidelines
- Follow the programming.dev instance rules
- Keep all content related to advent of code in some way
- If what youre posting relates to a day, put in brackets the year and then day number in front of the post title (e.g. [2023 Day 10])
- When an event is running, keep solutions in the solution megathread to avoid the community getting spammed with posts
Relevant Communities
Relevant Links
Credits
Icon base by Lorc under CC BY 3.0 with modifications to add a gradient
console.log('Hello World')
founded 1 year ago
MODERATORS
you are viewing a single comment's thread
view the rest of the comments
view the rest of the comments
My solution was worse than most: replace one -> one1one You are only going to do the replace all for each number and if the "e" is also in eight it is still there for the next set of replace.
A better quick and dirty solution from Mastodon was to just add the common character first: twone -> twoone
That's an esthetic abomination, but very clever
I have a friend who says that "whatever works is elegant" and solutions like OP's is why I simultaneously love and hate that phrase.
Behold, elegance:
digits = { "one": [1,2], "two": [2,2], "three": [3,4], "four": [4,3], "five": [5,3], "six": [6,2], "seven": [7,4], "eight": [8,4], "nine": [9,3], "1": [1,1], "2": [2,1], "3": [3,1], "4": [4,1], "5": [5,1], "6": [6,1], "7": [7,1], "8": [8,1], "9": [9,1] }and what comes afterwards is even more elegant, for it works!
I just check every substring haha
The problem is that 21 is not the only problematic combination.
You can also use o1e as there are never more than a single shared character. It also doesn't change the string size so it can be done in place. Still an ugly hack of a solution.