It's a little more complicated than that. You have to be summing everyone who is still tied to all the previous tracks. It needs to be a geometric sum formula.

[–] sabazius@lemmy.world 8 points 1 year ago* (last edited 1 year ago) (1 children)

It'll just be one fewer junctions. 2^n is always one more than the sum of 2^1+...2^(n-1)

[–] Magikjak@lemmy.world 1 points 1 year ago

I think you have to include 2^0 for that to be true?

e.g 2^0 = 1, 2^1 = 2 2^0 + 2^1 = 1 + 2 = 3, 2^2 = 4 … 7, 8 15,16 31, 32 etc.

[–] RatMaster@sh.itjust.works 5 points 1 year ago (1 children)

You could just move them over whenever someone decides to double it up. That way the person that was going to die alone is doomed to die anyway. 😂

[–] Patawagon@lemmy.world 3 points 1 year ago (1 children)

I wonder if we do stack it till every human is tied to the track whos at the lever?

Does the train/AI decide?

[–] fneu@discuss.tchncs.de 2 points 1 year ago

The current version of GPT is willing to sacrifice billions of robots for humanities sake. However, it proposed to strap alien civilizations to the track next. And in that case it would choose to save the larger group…