this post was submitted on 20 Nov 2024
338 points (98.6% liked)

Avatar: The Last Airbender

1327 readers
11 users here now

A community for all things related to Avatar: The Last Airbender, Legend of Korra, cartoon or live action TV, movies, comics, novels, etc.

Rules:

Please report any rule violations.

founded 2 years ago
MODERATORS
338
Me_irl (lemm.ee)
submitted 4 weeks ago* (last edited 4 weeks ago) by sag@lemm.ee to c/avatar@lemmy.world
 
you are viewing a single comment's thread
view the rest of the comments
[–] ArbitraryValue@sh.itjust.works 8 points 4 weeks ago (1 children)

rate of work = 1 / (deadline - current time)

[–] LeFantome@programming.dev 2 points 4 weeks ago (2 children)
[–] Snazz@lemmy.world 2 points 4 weeks ago* (last edited 4 weeks ago) (1 children)

Because there are no units, the equation can only be used to compare one rate of work to another rate of work at a different time (or a different deadline).

ratio of rate of work at time t1 compared to rate of work at time t2

= rate_of_work(t1, d) / rate_of_work(t2, d)

= (1 / (d - t1)) / (1 / (d - t2))

= (d - t2) / (d - t1)

This works because the only variables left are in the same units, even if that unit itself is unspecified.

[–] amon@lemmy.world 1 points 1 week ago

could a unit for this be s^-1^?

[–] tee9000@lemmy.world 1 points 4 weeks ago

Its a factor. It doesnt have a unit.