Science Memes

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if statement == false (i.imgflip.com)

submitted 2 weeks ago by tatterdemalion@programming.dev to c/science_memes@mander.xyz

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[–] juliebean@lemm.ee 62 points 2 weeks ago (16 children)

what would be the alternative? to always execute if the condition is true, but sometimes execute it even when false, for funsies?

[–] ptz@dubvee.org 40 points 2 weeks ago* (last edited 2 weeks ago) (9 children)

Hey, I like a little chaos in my codebase 😆

const funsies = () => (Math.round(Math.random() * 1000) % 2 == 0)
if ( condition || funsies() ) {
    // do the thing
}

[+] sorrybookbroke@sh.itjust.works 1 points 2 weeks ago* (last edited 2 weeks ago) (4 children)

[deleted]

[–] ptz@dubvee.org 3 points 2 weeks ago* (last edited 2 weeks ago) (1 children)

In Javascript, Math.random() produces a float value between 0 and 1, so I multiply by 1000 and round it to get a larger integer. The value %2 == 0 is a non-library way of performing isEven() on the random integer (value % 2 is 0 if even, 1 if odd, and the ==0 makes it return a boolean). When used in the if statement, it's essentially a coin flip.

[–] juliebean@lemm.ee 3 points 2 weeks ago (1 children)

does javascript not allow you to interpret integers as booleans in a conditions directly? seems it'd be simpler to just do math.round(math.random()), which should still get you true (1) or false (0) in equal likelihood. or am i missing something?

[–] ptz@dubvee.org 1 points 2 weeks ago* (last edited 2 weeks ago) (1 children)

It'll give you 1 ~= true or 0 ~= undefined, but I typically use Typescript which prefers actual booleans to boolean-ish

[–] juliebean@lemm.ee 1 points 2 weeks ago

huh. interesting. i wonder what number it's actually storing for false then?

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